3.447 \(\int x^4 (1-a^2 x^2)^{3/2} \tanh ^{-1}(a x) \, dx\)

Optimal. Leaf size=292 \[ -\frac{3 i \text{PolyLog}\left (2,-\frac{i \sqrt{1-a x}}{\sqrt{a x+1}}\right )}{128 a^5}+\frac{3 i \text{PolyLog}\left (2,\frac{i \sqrt{1-a x}}{\sqrt{a x+1}}\right )}{128 a^5}+\frac{\left (1-a^2 x^2\right )^{7/2}}{56 a^5}-\frac{3 \left (1-a^2 x^2\right )^{5/2}}{80 a^5}+\frac{\left (1-a^2 x^2\right )^{3/2}}{192 a^5}+\frac{3 \sqrt{1-a^2 x^2}}{128 a^5}-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)+\frac{3}{16} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{64 a^2}-\frac{3 x \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{128 a^4}-\frac{3 \tan ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right ) \tanh ^{-1}(a x)}{64 a^5} \]

[Out]

(3*Sqrt[1 - a^2*x^2])/(128*a^5) + (1 - a^2*x^2)^(3/2)/(192*a^5) - (3*(1 - a^2*x^2)^(5/2))/(80*a^5) + (1 - a^2*
x^2)^(7/2)/(56*a^5) - (3*x*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/(128*a^4) - (x^3*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/(6
4*a^2) + (3*x^5*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/16 - (a^2*x^7*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/8 - (3*ArcTan[Sq
rt[1 - a*x]/Sqrt[1 + a*x]]*ArcTanh[a*x])/(64*a^5) - (((3*I)/128)*PolyLog[2, ((-I)*Sqrt[1 - a*x])/Sqrt[1 + a*x]
])/a^5 + (((3*I)/128)*PolyLog[2, (I*Sqrt[1 - a*x])/Sqrt[1 + a*x]])/a^5

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Rubi [A]  time = 0.817538, antiderivative size = 292, normalized size of antiderivative = 1., number of steps used = 27, number of rules used = 7, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.318, Rules used = {6014, 6010, 6016, 266, 43, 261, 5950} \[ -\frac{3 i \text{PolyLog}\left (2,-\frac{i \sqrt{1-a x}}{\sqrt{a x+1}}\right )}{128 a^5}+\frac{3 i \text{PolyLog}\left (2,\frac{i \sqrt{1-a x}}{\sqrt{a x+1}}\right )}{128 a^5}+\frac{\left (1-a^2 x^2\right )^{7/2}}{56 a^5}-\frac{3 \left (1-a^2 x^2\right )^{5/2}}{80 a^5}+\frac{\left (1-a^2 x^2\right )^{3/2}}{192 a^5}+\frac{3 \sqrt{1-a^2 x^2}}{128 a^5}-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)+\frac{3}{16} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{64 a^2}-\frac{3 x \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{128 a^4}-\frac{3 \tan ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right ) \tanh ^{-1}(a x)}{64 a^5} \]

Antiderivative was successfully verified.

[In]

Int[x^4*(1 - a^2*x^2)^(3/2)*ArcTanh[a*x],x]

[Out]

(3*Sqrt[1 - a^2*x^2])/(128*a^5) + (1 - a^2*x^2)^(3/2)/(192*a^5) - (3*(1 - a^2*x^2)^(5/2))/(80*a^5) + (1 - a^2*
x^2)^(7/2)/(56*a^5) - (3*x*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/(128*a^4) - (x^3*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/(6
4*a^2) + (3*x^5*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/16 - (a^2*x^7*Sqrt[1 - a^2*x^2]*ArcTanh[a*x])/8 - (3*ArcTan[Sq
rt[1 - a*x]/Sqrt[1 + a*x]]*ArcTanh[a*x])/(64*a^5) - (((3*I)/128)*PolyLog[2, ((-I)*Sqrt[1 - a*x])/Sqrt[1 + a*x]
])/a^5 + (((3*I)/128)*PolyLog[2, (I*Sqrt[1 - a*x])/Sqrt[1 + a*x]])/a^5

Rule 6014

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(q_.), x_Symbol] :> Dist
[d, Int[(f*x)^m*(d + e*x^2)^(q - 1)*(a + b*ArcTanh[c*x])^p, x], x] - Dist[(c^2*d)/f^2, Int[(f*x)^(m + 2)*(d +
e*x^2)^(q - 1)*(a + b*ArcTanh[c*x])^p, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[c^2*d + e, 0] && GtQ[q
, 0] && IGtQ[p, 0] && (RationalQ[m] || (EqQ[p, 1] && IntegerQ[q]))

Rule 6010

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_)*Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[((f*x)^
(m + 1)*Sqrt[d + e*x^2]*(a + b*ArcTanh[c*x]))/(f*(m + 2)), x] + (Dist[d/(m + 2), Int[((f*x)^m*(a + b*ArcTanh[c
*x]))/Sqrt[d + e*x^2], x], x] - Dist[(b*c*d)/(f*(m + 2)), Int[(f*x)^(m + 1)/Sqrt[d + e*x^2], x], x]) /; FreeQ[
{a, b, c, d, e, f, m}, x] && EqQ[c^2*d + e, 0] && NeQ[m, -2]

Rule 6016

Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> -Sim
p[(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcTanh[c*x])^p)/(c^2*d*m), x] + (Dist[(b*f*p)/(c*m), Int[((f*x)^(m
- 1)*(a + b*ArcTanh[c*x])^(p - 1))/Sqrt[d + e*x^2], x], x] + Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)^(m - 2)*(a
+ b*ArcTanh[c*x])^p)/Sqrt[d + e*x^2], x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[c^2*d + e, 0] && GtQ[p,
0] && GtQ[m, 1]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 261

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rule 5950

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(-2*(a + b*ArcTanh[c*x])*
ArcTan[Sqrt[1 - c*x]/Sqrt[1 + c*x]])/(c*Sqrt[d]), x] + (-Simp[(I*b*PolyLog[2, -((I*Sqrt[1 - c*x])/Sqrt[1 + c*x
])])/(c*Sqrt[d]), x] + Simp[(I*b*PolyLog[2, (I*Sqrt[1 - c*x])/Sqrt[1 + c*x]])/(c*Sqrt[d]), x]) /; FreeQ[{a, b,
c, d, e}, x] && EqQ[c^2*d + e, 0] && GtQ[d, 0]

Rubi steps

\begin{align*} \int x^4 \left (1-a^2 x^2\right )^{3/2} \tanh ^{-1}(a x) \, dx &=-\left (a^2 \int x^6 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x) \, dx\right )+\int x^4 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x) \, dx\\ &=\frac{1}{6} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)+\frac{1}{6} \int \frac{x^4 \tanh ^{-1}(a x)}{\sqrt{1-a^2 x^2}} \, dx-\frac{1}{6} a \int \frac{x^5}{\sqrt{1-a^2 x^2}} \, dx-\frac{1}{8} a^2 \int \frac{x^6 \tanh ^{-1}(a x)}{\sqrt{1-a^2 x^2}} \, dx+\frac{1}{8} a^3 \int \frac{x^7}{\sqrt{1-a^2 x^2}} \, dx\\ &=-\frac{x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{24 a^2}+\frac{3}{16} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{5}{48} \int \frac{x^4 \tanh ^{-1}(a x)}{\sqrt{1-a^2 x^2}} \, dx+\frac{\int \frac{x^2 \tanh ^{-1}(a x)}{\sqrt{1-a^2 x^2}} \, dx}{8 a^2}+\frac{\int \frac{x^3}{\sqrt{1-a^2 x^2}} \, dx}{24 a}-\frac{1}{48} a \int \frac{x^5}{\sqrt{1-a^2 x^2}} \, dx-\frac{1}{12} a \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-a^2 x}} \, dx,x,x^2\right )+\frac{1}{16} a^3 \operatorname{Subst}\left (\int \frac{x^3}{\sqrt{1-a^2 x}} \, dx,x,x^2\right )\\ &=-\frac{x \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{16 a^4}-\frac{x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{64 a^2}+\frac{3}{16} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)+\frac{\int \frac{\tanh ^{-1}(a x)}{\sqrt{1-a^2 x^2}} \, dx}{16 a^4}+\frac{\int \frac{x}{\sqrt{1-a^2 x^2}} \, dx}{16 a^3}-\frac{5 \int \frac{x^2 \tanh ^{-1}(a x)}{\sqrt{1-a^2 x^2}} \, dx}{64 a^2}+\frac{\operatorname{Subst}\left (\int \frac{x}{\sqrt{1-a^2 x}} \, dx,x,x^2\right )}{48 a}-\frac{5 \int \frac{x^3}{\sqrt{1-a^2 x^2}} \, dx}{192 a}-\frac{1}{96} a \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-a^2 x}} \, dx,x,x^2\right )-\frac{1}{12} a \operatorname{Subst}\left (\int \left (\frac{1}{a^4 \sqrt{1-a^2 x}}-\frac{2 \sqrt{1-a^2 x}}{a^4}+\frac{\left (1-a^2 x\right )^{3/2}}{a^4}\right ) \, dx,x,x^2\right )+\frac{1}{16} a^3 \operatorname{Subst}\left (\int \left (\frac{1}{a^6 \sqrt{1-a^2 x}}-\frac{3 \sqrt{1-a^2 x}}{a^6}+\frac{3 \left (1-a^2 x\right )^{3/2}}{a^6}-\frac{\left (1-a^2 x\right )^{5/2}}{a^6}\right ) \, dx,x,x^2\right )\\ &=-\frac{\sqrt{1-a^2 x^2}}{48 a^5}+\frac{\left (1-a^2 x^2\right )^{3/2}}{72 a^5}-\frac{\left (1-a^2 x^2\right )^{5/2}}{24 a^5}+\frac{\left (1-a^2 x^2\right )^{7/2}}{56 a^5}-\frac{3 x \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{128 a^4}-\frac{x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{64 a^2}+\frac{3}{16} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{\tan ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{1+a x}}\right ) \tanh ^{-1}(a x)}{8 a^5}-\frac{i \text{Li}_2\left (-\frac{i \sqrt{1-a x}}{\sqrt{1+a x}}\right )}{16 a^5}+\frac{i \text{Li}_2\left (\frac{i \sqrt{1-a x}}{\sqrt{1+a x}}\right )}{16 a^5}-\frac{5 \int \frac{\tanh ^{-1}(a x)}{\sqrt{1-a^2 x^2}} \, dx}{128 a^4}-\frac{5 \int \frac{x}{\sqrt{1-a^2 x^2}} \, dx}{128 a^3}-\frac{5 \operatorname{Subst}\left (\int \frac{x}{\sqrt{1-a^2 x}} \, dx,x,x^2\right )}{384 a}+\frac{\operatorname{Subst}\left (\int \left (\frac{1}{a^2 \sqrt{1-a^2 x}}-\frac{\sqrt{1-a^2 x}}{a^2}\right ) \, dx,x,x^2\right )}{48 a}-\frac{1}{96} a \operatorname{Subst}\left (\int \left (\frac{1}{a^4 \sqrt{1-a^2 x}}-\frac{2 \sqrt{1-a^2 x}}{a^4}+\frac{\left (1-a^2 x\right )^{3/2}}{a^4}\right ) \, dx,x,x^2\right )\\ &=-\frac{\sqrt{1-a^2 x^2}}{384 a^5}+\frac{\left (1-a^2 x^2\right )^{3/2}}{72 a^5}-\frac{3 \left (1-a^2 x^2\right )^{5/2}}{80 a^5}+\frac{\left (1-a^2 x^2\right )^{7/2}}{56 a^5}-\frac{3 x \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{128 a^4}-\frac{x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{64 a^2}+\frac{3}{16} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{3 \tan ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{1+a x}}\right ) \tanh ^{-1}(a x)}{64 a^5}-\frac{3 i \text{Li}_2\left (-\frac{i \sqrt{1-a x}}{\sqrt{1+a x}}\right )}{128 a^5}+\frac{3 i \text{Li}_2\left (\frac{i \sqrt{1-a x}}{\sqrt{1+a x}}\right )}{128 a^5}-\frac{5 \operatorname{Subst}\left (\int \left (\frac{1}{a^2 \sqrt{1-a^2 x}}-\frac{\sqrt{1-a^2 x}}{a^2}\right ) \, dx,x,x^2\right )}{384 a}\\ &=\frac{3 \sqrt{1-a^2 x^2}}{128 a^5}+\frac{\left (1-a^2 x^2\right )^{3/2}}{192 a^5}-\frac{3 \left (1-a^2 x^2\right )^{5/2}}{80 a^5}+\frac{\left (1-a^2 x^2\right )^{7/2}}{56 a^5}-\frac{3 x \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{128 a^4}-\frac{x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{64 a^2}+\frac{3}{16} x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{1}{8} a^2 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-\frac{3 \tan ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{1+a x}}\right ) \tanh ^{-1}(a x)}{64 a^5}-\frac{3 i \text{Li}_2\left (-\frac{i \sqrt{1-a x}}{\sqrt{1+a x}}\right )}{128 a^5}+\frac{3 i \text{Li}_2\left (\frac{i \sqrt{1-a x}}{\sqrt{1+a x}}\right )}{128 a^5}\\ \end{align*}

Mathematica [A]  time = 1.33109, size = 272, normalized size = 0.93 \[ \frac{-315 i \text{PolyLog}\left (2,-i e^{-\tanh ^{-1}(a x)}\right )+315 i \text{PolyLog}\left (2,i e^{-\tanh ^{-1}(a x)}\right )-240 a^6 x^6 \sqrt{1-a^2 x^2}+216 a^4 x^4 \sqrt{1-a^2 x^2}+218 a^2 x^2 \sqrt{1-a^2 x^2}+121 \sqrt{1-a^2 x^2}-1680 a^7 x^7 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)+2520 a^5 x^5 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-210 a^3 x^3 \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-315 a x \sqrt{1-a^2 x^2} \tanh ^{-1}(a x)-315 i \tanh ^{-1}(a x) \log \left (1-i e^{-\tanh ^{-1}(a x)}\right )+315 i \tanh ^{-1}(a x) \log \left (1+i e^{-\tanh ^{-1}(a x)}\right )}{13440 a^5} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[x^4*(1 - a^2*x^2)^(3/2)*ArcTanh[a*x],x]

[Out]

(121*Sqrt[1 - a^2*x^2] + 218*a^2*x^2*Sqrt[1 - a^2*x^2] + 216*a^4*x^4*Sqrt[1 - a^2*x^2] - 240*a^6*x^6*Sqrt[1 -
a^2*x^2] - 315*a*x*Sqrt[1 - a^2*x^2]*ArcTanh[a*x] - 210*a^3*x^3*Sqrt[1 - a^2*x^2]*ArcTanh[a*x] + 2520*a^5*x^5*
Sqrt[1 - a^2*x^2]*ArcTanh[a*x] - 1680*a^7*x^7*Sqrt[1 - a^2*x^2]*ArcTanh[a*x] - (315*I)*ArcTanh[a*x]*Log[1 - I/
E^ArcTanh[a*x]] + (315*I)*ArcTanh[a*x]*Log[1 + I/E^ArcTanh[a*x]] - (315*I)*PolyLog[2, (-I)/E^ArcTanh[a*x]] + (
315*I)*PolyLog[2, I/E^ArcTanh[a*x]])/(13440*a^5)

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Maple [A]  time = 0.213, size = 215, normalized size = 0.7 \begin{align*} -{\frac{1680\,{\it Artanh} \left ( ax \right ){x}^{7}{a}^{7}+240\,{x}^{6}{a}^{6}-2520\,{\it Artanh} \left ( ax \right ){x}^{5}{a}^{5}-216\,{x}^{4}{a}^{4}+210\,{a}^{3}{x}^{3}{\it Artanh} \left ( ax \right ) -218\,{a}^{2}{x}^{2}+315\,ax{\it Artanh} \left ( ax \right ) -121}{13440\,{a}^{5}}\sqrt{- \left ( ax-1 \right ) \left ( ax+1 \right ) }}-{\frac{{\frac{3\,i}{128}}{\it Artanh} \left ( ax \right ) }{{a}^{5}}\ln \left ( 1+{i \left ( ax+1 \right ){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) }+{\frac{{\frac{3\,i}{128}}{\it Artanh} \left ( ax \right ) }{{a}^{5}}\ln \left ( 1-{i \left ( ax+1 \right ){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) }-{\frac{{\frac{3\,i}{128}}}{{a}^{5}}{\it dilog} \left ( 1+{i \left ( ax+1 \right ){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) }+{\frac{{\frac{3\,i}{128}}}{{a}^{5}}{\it dilog} \left ( 1-{i \left ( ax+1 \right ){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(-a^2*x^2+1)^(3/2)*arctanh(a*x),x)

[Out]

-1/13440/a^5*(-(a*x-1)*(a*x+1))^(1/2)*(1680*arctanh(a*x)*x^7*a^7+240*x^6*a^6-2520*arctanh(a*x)*x^5*a^5-216*x^4
*a^4+210*a^3*x^3*arctanh(a*x)-218*a^2*x^2+315*a*x*arctanh(a*x)-121)-3/128*I*ln(1+I*(a*x+1)/(-a^2*x^2+1)^(1/2))
*arctanh(a*x)/a^5+3/128*I*ln(1-I*(a*x+1)/(-a^2*x^2+1)^(1/2))*arctanh(a*x)/a^5-3/128*I*dilog(1+I*(a*x+1)/(-a^2*
x^2+1)^(1/2))/a^5+3/128*I*dilog(1-I*(a*x+1)/(-a^2*x^2+1)^(1/2))/a^5

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}} x^{4} \operatorname{artanh}\left (a x\right )\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(-a^2*x^2+1)^(3/2)*arctanh(a*x),x, algorithm="maxima")

[Out]

integrate((-a^2*x^2 + 1)^(3/2)*x^4*arctanh(a*x), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-{\left (a^{2} x^{6} - x^{4}\right )} \sqrt{-a^{2} x^{2} + 1} \operatorname{artanh}\left (a x\right ), x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(-a^2*x^2+1)^(3/2)*arctanh(a*x),x, algorithm="fricas")

[Out]

integral(-(a^2*x^6 - x^4)*sqrt(-a^2*x^2 + 1)*arctanh(a*x), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(-a**2*x**2+1)**(3/2)*atanh(a*x),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}} x^{4} \operatorname{artanh}\left (a x\right )\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(-a^2*x^2+1)^(3/2)*arctanh(a*x),x, algorithm="giac")

[Out]

integrate((-a^2*x^2 + 1)^(3/2)*x^4*arctanh(a*x), x)